Indian National Flag Visualization with Ashoka Chakra using Python's Matplotlib

 

 Indian National Flag Visualization with Ashoka Chakra using Python's Matplotlib

Description:

In this post, we present a Python code snippet that uses the powerful Matplotlib library to generate a visual representation of the Indian national flag, complete with the iconic Ashoka Chakra. The code intelligently constructs the flag's three horizontal stripes – green, white, and saffron – along with the 24 spokes of the Ashoka Chakra. Through the use of trigonometry and geometric shapes, this Python visualization pays homage to the esteemed national flag of India. The step-by-step code and detailed explanation make it accessible for both beginners and experienced programmers to understand the process behind this patriotic artwork.

Installation:

pip install numpy

pip install matplotlib

Source Code:

s

import numpy as np
import matplotlib.pyplot as py
import matplotlib.patches as patch

a = patch.Rectangle((0,1), width=12, height=2, facecolor='green', edgecolor='grey')
b = patch.Rectangle((0,3), width=12, height=2, facecolor='white', edgecolor='grey')
c = patch.Rectangle((0,5), width=12, height=2, facecolor='#FF9933', edgecolor='grey')

m,n= py.subplots()
n.add_patch(a)
n.add_patch(b)
n.add_patch(c)
radius=0.8

py.plot(6,4, marker= 'o',markerfacecolor='#000088FF', markersize=9.5)
chakra= py.Circle((6, 4), radius, color='#000088ff', fill=False, linewidth=7)
n.add_artist(chakra)

for i in range(0, 24):

    p= 6 + radius/2 * np.cos(np.pi*i/12 + np.pi/48)
    q= 6 + radius/2 * np.cos(np.pi*i/12 - np.pi/48)
    r= 4 + radius/2 * np.sin(np.pi*i/12 + np.pi/48)
    s= 4 + radius/2 * np.sin(np.pi*i/12 - np.pi/48)
    t= 6 + radius * np.cos(np.pi*i/12)
    u= 4 + radius * np.sin(np.pi*i/12)
    n.add_patch(patch.Polygon([[6,4],[p,r],[t,u],[q,s]], fill=True, closed=True, color="#000088FF")) 

py.axis('equal')
py.show()